joyseychow wrote:If the eleven consecutive integers are listed from least to greatest, what is the average (arithmetic mean) of eleven integers?
(1) The average of the first nine integers is 7
(2) The average of the last nine integers is 9
Looks like
D
Consecutive integers ,mean=median
1. As the number are arranged in order, mean= median ¨=7 and we are talking about first nine integrs
so 7 is in the middle of 9 integers
so list is 3 4 5 6
7 8 9 10 11..and other 2 integers are 12 and 13
so complete list 3 4 5 6 7 8 9 10 11 12 13
we can now find average
sufficient
2. similarly, when The average of the last nine integers is 9
the last 9 integers would be 5 6 7 8 9 10 11 12 13
so complete list is 3 4 5 6 7 8 9 10 11 12 13