2^(x+y)²/ 2^(x-y)² = 2^(x² + 2xy + y²)/ 2^(x² - 2xy + y²)if xy=1 then what is the value of 2^(x+y)²/ 2^(x-y)²
1)2
2) 4
3) 8
4) 16
5) 32
= 2^(4xy) [after we SUBTRACT exponents]
= 2^4 [since xy = 1]
= 16
Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
