Please post the problem itself, not just the question number.
Here is DS104 in the OG13:
If [x] denotes the greatest integer less than or equal to x , is [x] =0?
(1) 5x + 1 = 3 + 2x
(2) 0 < x < 1
{x} = 0 implies that the GREATEST INTEGER LESS THAN OR EQUAL TO X is 0.
If 0≤x≤1, then the greatest integer less than or equal to x is 0.
Consider the following cases:
x=0 -------> The greatest integer less than or equal to 0 is 0.
x=0.0001 --> The greatest integer less than or equal to 0.0001 is 0.
x=0.9999 --> The greatest integer less than or equal to 0.9999 is 0.
If x<0 or x≥1, then the greatest integer less than or equal to x will NOT be 0.
Question stem, rephrased:
Is 0≤x≤1?
Statement 1: 5x + 1 = 3 + 2x
Since we can solve for x, we can determine whether 0≤x<1.
SUFFICIENT.
Statement 2: 0 < x < 1
SUFFICIENT.
The correct answer is
D.
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