I assumed the perimeter of the triangle to be 24; which gives
AB = BC = AC = 8
Image attached!
Draw a perpendicular from A so that is bisects B & C at point D and where it touches the circle as point E.
BD = CD = 4
as AB = 8, BD = 4,
Using pythagoras, AD approx is 7
Lets take center of the circle as O,
OD = DE = 3.5
AE = AD + DE
= 7 + 3.5
= 10.5 Approx 11
Please comment.
Ans C.
GMAT Prep - Triangle inscribed in circle question
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ssy
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Thanks a lot Suyong and Ri 2007.
Ri2007 - How do you know that " Arc ABC = 24 so circumference = 24+12 =36"
Is it because the circle is inscribed with an equilateral triangle..and arc ABC "covers" 2 sides out of 3 sides of the triangle...which means Arc ABC =2/3 of circumference?
Ri2007 - How do you know that " Arc ABC = 24 so circumference = 24+12 =36"
Is it because the circle is inscribed with an equilateral triangle..and arc ABC "covers" 2 sides out of 3 sides of the triangle...which means Arc ABC =2/3 of circumference?
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gmatguy16
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i agree with ri,not too sure about suyog,
the question says length of arc ,which is lot different than perimeter of triangle..so maybe you got same answer which was a coincidence..guys please let me know i am thinking okay?
the question says length of arc ,which is lot different than perimeter of triangle..so maybe you got same answer which was a coincidence..guys please let me know i am thinking okay?












