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by ketkoag » Sun Sep 06, 2009 9:15 am
i assumed that both the triangles are isoceles triangles and then used area of the triangles.
please explain whether i assumed correctly..
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hmm

by JeffB » Sun Sep 06, 2009 2:33 pm
Since the ratio of the areas is 2:1 - The ratios of the side lengths is simply: squareroot(2):squareroot (1):

So,

S = Squareroot(2) * s

Just remember, the connection between the areas and the side lengths is simply the side lengths squared, for similar triangles.

For instance:

If we have a 9,12,15 triangle and a 3,4,5.

A = 1/2 * 9 * 12 = 54
A = 1/2 * 3 * 4 = 6

Area ratio 9:1

And notice the ratio for the sides is 3:1 - Simply the square root, or to get the 9:1 ratio we simply square the 3:1 ratio.

I hope that helps.
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by kbharadwaj.1987 » Sun Sep 06, 2009 3:27 pm
I think it's 2s. What's the OA?
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