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great work thoughliferocks wrote:if 4^p X (1/3) ^q < 1
we get (4/3)^p *(1/3)^(q-p)<1
since 4/3 >1 and p is positive (only positive or integer too?),(4/3)^p>1..hence (1/3)^(q-p)<1 or q-p>0 or q>p
From 1
q>p..sufficient
From 2
No info about p...nit sufficient
Ans option A
edited.sanju09 wrote:great work thoughliferocks wrote:if 4^p X (1/3) ^q < 1
we get (4/3)^p *(1/3)^(q-p)<1
since 4/3 >1 and p is positive (only positive or integer too?),(4/3)^p>1..hence (1/3)^(q-p)<1 or q-p>0 or q>p
From 1
q>p..sufficient
From 2
No info about p...nit sufficient
Ans option A
Want to edit more? What is "nit"?liferocks wrote:if 4^p X (1/3) ^q < 1
we get (4/3)^p *(1/3)^(q-p)<1
since 4/3 >1 and p is positive integer,(4/3)^p>1..hence (1/3)^(q-p)<1 or q-p>0 or q>p
From 1
q>p..sufficient
From 2
No info about p...nit sufficient
Ans option A
Again edited!!..hope nothing else is left to edit.sanju09 wrote:
Want to edit more? What is "nit"?
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