Arco question

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Arco question

by priyankamishra11 » Mon Sep 15, 2008 7:11 pm
On a soccer team consisting of 21 children, some of which are boys and some of which are girls, exactly of the boys and exactly of the girls attended the end of the season pizza party. What is the greatest number of children on the team who could have attended the party?
11
12
13
14
15
Regards,
Priyanka
Source: — Problem Solving |

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by cramya » Mon Sep 15, 2008 8:58 pm
Priyanka,
Is this a complete question? It reads exactly of the boys and exactly of the girls??

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by parallel_chase » Mon Sep 15, 2008 10:50 pm
Here is the correct question

On a Soccer team consisting of 21 children, some of which are boys and some of which are girls,exactly 2/3 of the boys and exactly 1/3 of the girls attended the end of the season pizza party.What is the greatest number of children on team who could have attended the party?

Kindly check before posting!

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by nil4700 » Mon Sep 15, 2008 11:00 pm
let the no of boys be B and the no of girl be G.

B+G = 21.

2/3 * B + 1/3 * G should be maximum.

that means B and G should be multiples of 3.

possibilities are (B,G)==>: (3,18), (6,15), (9,12),(12,9),(15,6), (18,3).

For the sum 2/3*B+1/3 *G to be maximum B should have the highest value possible which is 18 and G will be 3 then:

2/3*18 + 1/3*3 = 12+1 = 13

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by parallel_chase » Mon Sep 15, 2008 11:24 pm
Let x be total number of boys

then, 21-x = total number of girls

total number of boys attended the party = 2x/3
total number of girls attended the party = (21-x)/3

Since 2/3 boys and 1/3 girls attended the party, to find out the greatest number of people attended the party we have to find the greatest number of boys.

Just plugin the answer choices to get the answer.

2x/3 + (21-x)/3 = 13

x= 18, 21-x = 3


Hope this helps.

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by mayur00 » Tue Sep 16, 2008 10:05 am
Since 2/3 is a bigger fraction than 1/3, so maximize the number of boys in the team keeping the number of girls divisible by three.

18 boys and 3 girls will be the first and the correct split.

Therefore 2/3*18 + 1/3*3 = 13 is the greatest number of children on the team who attend the party.