practice question 55

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by niraj_a » Fri Aug 29, 2008 4:07 pm
try substituting 8 for t in the given equation, and then solve for k.

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by 4meonly » Mon Sep 01, 2008 12:41 am
(t^2)- kt-48 = (t+6)(t-8 )
because we know that (t-8 ) is a factor of (t^2)- kt-48
solving (t+6)(t-8 ) = (t^2)-8t+6t-48 = t^2-2t-48

k=2

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by canuckclint » Wed Sep 03, 2008 6:09 pm
niraj_a wrote:try substituting 8 for t in the given equation, and then solve for k.

Yes, if 8 is a root.
Then t-8 = 0.
t = 8