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Probabilty pt question

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Probabilty pt question

by jc114 » Mon Apr 16, 2007 2:50 pm
Team Number of games won
A 4
B 7
C 9
D 2
E 2
X

Accoording to the incomplete table above, if each of the 6 teams in the league played each of the other teams exactly twice and there were no ties, how many games did team X win? (Only 2 teams play in a game).

A. 4
B. 5
C. 6
D. 8
E. 10

it seems easy..but then i got stuck...
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Re: Probabilty pt question

by jayhawk2001 » Mon Apr 16, 2007 7:44 pm
jc114 wrote:Team Number of games won
A 4
B 7
C 9
D 2
E 2
X

Accoording to the incomplete table above, if each of the 6 teams in the league played each of the other teams exactly twice and there were no ties, how many games did team X win? (Only 2 teams play in a game).

A. 4
B. 5
C. 6
D. 8
E. 10

it seems easy..but then i got stuck...
I'm getting 6. Is the answer C ?

Each team plays each of the other team implies total number of games
= 6C2 = 15. Since this happens twice, total number of games = 30.

Tallying up the number of games won we get 24 (4 + 7 + 9 + 2 + 2)

So, the remaining 6 games were won by team X.
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by Kuba » Mon Apr 16, 2007 11:21 pm
I got the same answer, 6.
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by Cybermusings » Tue Apr 17, 2007 2:52 am
Total games played if each team plays each of the other team exactly once = 6C2=15
Since each team plays each of the other atleast 2 times - Games played = 15*2=30
Hence games won by X should be 30-24=6
What's the OA?
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by jc114 » Wed Apr 18, 2007 3:44 pm
thanks~ c is right!
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by f2001290 » Sun May 27, 2007 3:30 am
Jay and Cybermusings

don't you think the total number of games won by A is 10.

6 remaining games and 4 games which it has already won.
That makes it 10.
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by gabriel » Sun May 27, 2007 6:26 am
f2001290 wrote:Jay and Cybermusings

don't you think the total number of games won by A is 10.

6 remaining games and 4 games which it has already won.
That makes it 10.
the q asks for the number of games X won ....
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