solving for m/102
102 = 2* 3 * 17
so if m has at least one 2, one 3 and one 17 in its factor then m is divisible by 102.
statement 1
165 = 5 * 3 * 11 and 99 = 3 * 3 * 11
so when we say 99 is a factor of 165 * M we mean that 165 *M will have at least this 3 * 3 * 11. now we know that 165 has one 3 and one 11 as a factor so other 3 of 99 is coming from M.
we have 3 as one of the factor of M but we don't know that whether 2 and 17 are factors of M.
Not Sufficient.
Statement 2:
34 = 2 * 17
for 34 to be a factor of 7 * M , M must has one 2 and one 17 as its factor.
but we don't know whether 3 is a factor of M
Not sufficient.
now combing both statement
from 1st statement we know that 3 is the factor of M and from 2nd statement we know that 2 and 17 are factor of M. hence m is divisible by 102.
Option C
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