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aritmetic mean=(3+k+2+8+m+3)/6Panaac wrote:Can someone please solve this problem for me?
3 K 2 8 M 3
The arithmetic mean of the list of numbers above is 4. If K and M are integers, and K ≠M, what is the median of the list?
a) 2
b) 2.5
c) 3
d) 3.5
e) 4
The answer is C.
k and m integer means it can be 0 or -negative but in this case it wont be therePanaac wrote:Thank you so much, amissing6!
I just have 1 question. When it says K and M are integers, does it means K and M can be negative or 0?
well it can mean. however result won't change.Panaac wrote:Thank you so much, amissing6!
I just have 1 question. When it says K and M are integers, does it means K and M can be negative or 0?
median is the middle number in odd set, or the average of two middle numbers in even set, then on some level answer has to be 3, which is C. K and M would have to be elements that are both below three or both above three to change the value of the median. but since both K+M=8, all combinations of K and M that can add up to 8 don't disturb the median i.e. 1+7, 2+6, 3+5, 5+3, 6+2, 7+1, etc.Panaac wrote:Can someone please solve this problem for me?
3 K 2 8 M 3
The arithmetic mean of the list of numbers above is 4. If K and M are integers, and K ≠M, what is the median of the list?
a) 2
b) 2.5
c) 3
d) 3.5
e) 4
The answer is C.
We can create the following equation:Panaac wrote:Can someone please solve this problem for me?
3 K 2 8 M 3
The arithmetic mean of the list of numbers above is 4. If K and M are integers, and K ≠M, what is the median of the list?
a) 2
b) 2.5
c) 3
d) 3.5
e) 4
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