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by likewhoa » Fri Nov 23, 2007 12:34 am
√[2√63 + 2/(8+3√7)] =

A. 8 + 3√7
B. 4 + 3√7
C. 8
D. 4
E. √7
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by sujaysolanki » Fri Nov 23, 2007 1:26 am
If we take root 63 to be approx 8 it comes to D .

2 * 8 + 2/16
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by gabriel » Fri Nov 23, 2007 7:36 am
Well, there is a pure algebraic solution to this, but I would choose the previous posters method of approximating root(63)= 8 over the algebraic solution..If anyone wants to know the algebraic solution, I would be happy to illustrate it.

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by lawalx » Sat Nov 24, 2007 12:00 am
please illustrate it
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by gmatguy16 » Wed Nov 28, 2007 6:19 pm
if we multiply both the numerator and denominator by8-3 sqrt(7) ..we get
sqrt ( 16/1) = 4
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