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GMATPrep 3
Source: Beat The GMAT — Problem Solving |
Now h(100) = 2*4*6 ....... 96*98*100. The maximum possible prime factor for h(100) can be calculated by trying 98/2 = 49 (not prime), 94/2 = 47 (prime).
So maximum possible prime factor of h(100) =47. so h(100) is a multiple of 47(and all primes less than 47), hence h(100)+1 cannot be a multiple of 47 (or primes less than 47).
Since p is a prime factor of h(100)+1, so p should atleast be greater than 47 to be a prime factor of h(100)+1. hence p>47.
Hope this helps
hence p>47
So maximum possible prime factor of h(100) =47. so h(100) is a multiple of 47(and all primes less than 47), hence h(100)+1 cannot be a multiple of 47 (or primes less than 47).
Since p is a prime factor of h(100)+1, so p should atleast be greater than 47 to be a prime factor of h(100)+1. hence p>47.
Hope this helps
hence p>47
