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by camitava » Thu Sep 18, 2008 5:36 pm
Guys, I dnt know whether this Qs has already been asked here! I tried to search in this forum but with no result. However, the Qs is -


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OA is D
Correct me If I am wrong


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Amitava
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by stop@800 » Thu Sep 18, 2008 10:18 pm
slope = -3/5
and y intercept = 30

so eqn of line
3x+5y = 150

y = (150-3x)/5

for y to be integer x has to be multiple of 5
x varies from 0 to 50
so 11 possible values of x: 0 5 10 15 . . . . . 45

Whats the OA?
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by camitava » Fri Sep 19, 2008 4:15 am
Got it sir! Yes the OA is D ...
Correct me If I am wrong


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Amitava
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by Indradeep » Fri Sep 19, 2008 4:21 am
It is 11 points because any point on the line (x,y) is in the ration of 5:3
Thus x = (5/3)y which is only possible if y = multiple of 3 from 0->30 including both, i.e. 11 points.
Thus D
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