BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Inequalities:

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Junior | Next Rank: 30 Posts
Posts: 26
Joined: Wed Apr 30, 2008 11:05 am
Location: India
by anksbhandari » Thu Jul 17, 2008 9:15 am
Please Explain,

a, b, and c are integers and a < b < c. S is the set of all integers from a to b, inclusive. Q is the
set of all integers from b to c, inclusive. The median of set S is (3/4)b. The median of set Q is
(7/8)c. If R is the set of all integers from a to c, inclusive, what fraction of c is the median of set
R?
(A) 3/8
(B) 1/2
(C) 11/16
(D) 5/7
(E) 3/4
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Senior | Next Rank: 100 Posts
Posts: 66
Joined: Tue Jun 05, 2007 1:39 pm
Thanked: 1 times

what number represents smiley face? please provide. thanks.

by hakyology » Thu Jul 17, 2008 10:13 am
can't do it without real smiley face number, i think.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 1153
Joined: Wed Jun 20, 2007 6:21 amFollowed by: 2 members
Thanked: 146 times

Re: Inequalities:

by parallel_chase » Thu Jul 17, 2008 10:32 am
anksbhandari wrote:Please Explain,

a, b, and c are integers and a < b < c. S is the set of all integers from a to b, inclusive. Q is the
set of all integers from b to c, inclusive. The median of set S is (3/4)b. The median of set Q is
(7/8)c. If R is the set of all integers from a to c, inclusive, what fraction of c is the median of set
R?
(A) 3/8
(B) 1/2
(C) 11/16
(D) 5/7
(E) 3/4
From next time kindly disable the smilies before posting the question.

Is the answer 11/16?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 189
Joined: Thu May 01, 2008 10:55 pmFollowed by: 1 member
Location: Seattle, WA
Thanked: 25 times
GMAT Score:750+

by VP_Tatiana » Thu Jul 17, 2008 10:41 am
Hi Parallel,

I was unable to solve your problem because one of the numbers was mistyped and displayed a smiley face instead! Could you please retype your question? Thanks!

Tatiana
Tatiana Becker | GMAT Instructor | Veritas Prep
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 1153
Joined: Wed Jun 20, 2007 6:21 amFollowed by: 2 members
Thanked: 146 times

by parallel_chase » Thu Jul 17, 2008 10:45 am
VP_Tatiana wrote:Hi Parallel,

I was unable to solve your problem because one of the numbers was mistyped and displayed a smiley face instead! Could you please retype your question? Thanks!

Tatiana
(7/8)c

The code for the smily is /8)

I guess the answer is 11/16, let me know what you think.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 66
Joined: Tue Jun 05, 2007 1:39 pm
Thanked: 1 times

I agree.

by hakyology » Thu Jul 17, 2008 11:14 am
I agree. I got 11/16.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 320
Joined: Sun Jan 13, 2008 10:00 pm
Thanked: 10 times

by ildude02 » Thu Jul 17, 2008 2:05 pm
With 7/8, I got 1/2 as the answer. Can you please tell how you got 11/16? I solved it using numbers. So it wasn't the fastest way.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 26
Joined: Wed Apr 30, 2008 11:05 am
Location: India

Repeat questions

by anksbhandari » Sat Jul 19, 2008 2:58 am
a, b, and c are integers and a < b < c. S is the set of all integers from a to b, inclusive. Q is the
set of all integers from b to c, inclusive. The median of set S is (3/4)b. The median of set Q is
(7/8)c. If R is the set of all integers from a to c, inclusive, what fraction of c is the median of set
R?
(A) 3/8
(B) 1/2
(C) 11/16
(D) 5/7
(E) 3/4
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 26
Joined: Wed Apr 30, 2008 11:05 am
Location: India

The figure behind : (7/8)C

by anksbhandari » Sat Jul 19, 2008 3:00 am
The fraction behind smiling face is (7/8) C
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 26
Joined: Wed Apr 30, 2008 11:05 am
Location: India

OA

by anksbhandari » Sat Jul 19, 2008 3:05 am
( The fraction behind smiliy is (7/8) C)

OA is option C 6/11
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 1153
Joined: Wed Jun 20, 2007 6:21 amFollowed by: 2 members
Thanked: 146 times

Re: OA

by parallel_chase » Sat Jul 19, 2008 3:09 am
anksbhandari wrote:( The fraction behind smiliy is (7/8) C)

OA is option C 6/11
Option C is 11/16.

To disable the smily, while posting just check the option " diable the smily"
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 320
Joined: Sun Jan 13, 2008 10:00 pm
Thanked: 10 times

by ildude02 » Sat Jul 19, 2008 8:52 am
Can someone solve the problem? I wanted to see if my apprach is different and if there is an easier way to solve then by choosing numbers.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 1153
Joined: Wed Jun 20, 2007 6:21 amFollowed by: 2 members
Thanked: 146 times

by parallel_chase » Sat Jul 19, 2008 11:52 am
ildude02 wrote:Can someone solve the problem? I wanted to see if my apprach is different and if there is an easier way to solve then by choosing numbers.
S [a-b] = 3/4 b

(a+b)/2 = 3/4 b
2a = b

Q [b-c] = 7/8 c

(b+c)/2 = 7/8 c

b=3/4 c

Therefore,

a=3/8 c
b= 3/4 c

R [a-c] = ?

(a+c)/2 = [(3/8)c +c]/2 = (11/16) c

Hence C is the answer.

let me know if you have any questions.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 320
Joined: Sun Jan 13, 2008 10:00 pm
Thanked: 10 times

by ildude02 » Sat Jul 19, 2008 12:28 pm
Thanks for your explanation. I assume you based it on the theory that Average of consecutive integers is equal to Median ? Not sure how I missed it, damn!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1