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sportypk: Junior | Next Rank: 30 Posts; Posts: 15; Joined: Mon Mar 31, 2008 11:01 amFollowed by: 1 member

by sportypk » Sat May 31, 2008 12:01 pm

I m fairly new here posting thanks for the headsup.

3. If x≠0, is |x| <1?
(1) x^2<1
(2) |x| < 1/x

OA is D

Could someone explain this

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Source: Beat The GMAT — Problem Solving | Sat May 31, 2008 12:01 pm

netigen: Legendary Member; Posts: 631; Joined: Mon Feb 18, 2008 11:57 pmFollowed by: 3 members; Thanked: 29 times

by netigen » Sat May 31, 2008 12:57 pm

Question rephrase: is -1<x<1 ?

(a) this is straightforward as x will be between -1 and 1 so suff

(b) |x| < 1/x
when x = +ve
x < 1/x or x^2 < 1 so sufficient
when x = -ve
-x < 1/x or -x^2 > 1 or x^2 < -1 this is a not possible case hence reject
so B is also sufficient.

I think plugging numbers would have been an easier approach in this case

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