Sweater sale

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Sweater sale

by Xbond » Wed Jun 10, 2009 12:31 pm
Hi there,

I didn't succeed to put a clear equation and relation with sell price, cost purchase, total revenue...

Could you explain a simple way to resolve it and the concept

During a one-day sale, a store sold each sweater of cer tain type for 30$ more than the store's cost to purchase each sweater. How many of these sweaters were sold during the sale ?

(1) During the sale, the total revenue from the sale of these sweaters was $270

(2) During the sale, the store sold each of these sweaters at a price that was 50 percent greather than the store's cost to purchase each sweater.


Answer C
Source: — Data Sufficiency |

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by Sher1 » Wed Jun 10, 2009 1:32 pm
From the question you can set up this eq

P=C+30

1. Rev = P*Q
270= (C+30)Q

no suffi

2. P = 0.5C
Using the equ P=C+30, we can find C. But not enough to find the Q
C = 60

From 1 and 2
270=90Q
Q=3

C

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by Xbond » Thu Jun 11, 2009 12:03 pm
Yes, you're right. I fix it now :


In 1995 Division A of Company X had 4 850 customers. if there were 86 service errors in Division A that year, what was the service-error rate, in number of service errors per 100 customers, for Division B of company X in 1995 ?

(1) In 1995, the overall service-error rate for Divisions A and B combined was 1.5 service errors per 100 customers

(2) In 1995 Division B had 9 350 customers, none of whom were customers of Division A