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Positive Integer

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Source: — Data Sufficiency |
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by Suyog » Tue Aug 05, 2008 10:06 am
II) q = 2^k, where k is positive int.

k can be 2, 3, 4
so, q will be 4, 8, 16

17 divided by q will always give 1 as remainder, r = 1.

choose(b).

If b is the answer you can not choose c.

priority of choosing the answer should be as follows:

a
d
b
c
e
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by codesnooker » Thu Aug 07, 2008 1:40 am
Suyog wrote:II) q = 2^k, where k is positive int.

k can be 2, 3, 4
so, q will be 4, 8, 16

17 divided by q will always give 1 as remainder, r = 1.

choose(b).

If b is the answer you can not choose c.

priority of choosing the answer should be as follows:

a
d
b
c
e
I am sorry to say Suyog, but again you are judging question by seeing the answers.

according to question, k is a positive integer. so why can't k = 0. and if k=0 then remainder will be 0, not 1.

Now don't say that k can't be zero. As zero is positive even integer.
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by Vignesh.4384 » Thu Aug 07, 2008 2:01 am
codesnooker,

Zero is not positive or negative..
Postive integers start from 1
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by codesnooker » Thu Aug 07, 2008 2:07 am
Hmm. got it. I just searched on the wiki. Zero is even number but not a positive or negative integer. Thanks
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