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by vladmire » Sun Dec 07, 2008 5:16 pm
A recent lunch meeting at a certain club was attended by members and guests. Each member paid $4 for the lunch and each guest paid $8 for the lunch. How many of the people attending the meeting were members

(1) A total of 20 people attended the meeting.

(2) A total of $92 was paid for the lunch

a
b
c
d
e


sigh I cant figure out the equation both combining the 1 and 2 oa =c
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Source: — Data Sufficiency |
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by cramya » Sun Dec 07, 2008 5:24 pm
Let M be the members
Let G be the guest

Stmt I

M+G = 20

Any combination possible

Stmt II

4M+8G=92

(28+64=92 i.e 7 members 8 guests or 36+56 i.e. 9 members 7 guests possible)

INSUFF


Combined stm i and ii

M+G = 20
4M+8G=92
Can be solved for M and G

Choose C)
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