Here the step involves substituting 1-x for x in function equation.
Suppose f(x)=1-x
Now sub 1-x for x then f(1-x)=1-(1-x)=x
f(x)!=f(1-x)
Only D satisfy the condition.
f(x)=x^2(1-x)^2
f(1-x)=(1-x)^2(1-(1-x))^2(1-x)^2.X^2
f(x)=f(1-x)
Pick D
gmatprep - functions
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- goyalsau
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selango wrote:Here the step involves substituting 1-x for x in function equation.
Suppose f(x)=1-x
Now sub 1-x for x then f(1-x)=1-(1-x)=x
f(x)!=f(1-x)
Only D satisfy the condition.
f(x)=x^2(1-x)^2
f(1-x)=(1-x)^2(1-(1-x))^2(1-x)^2.X^2
f(x)=f(1-x)
Pick D
Can you please explain this step,
and is there any other way to solve these type of questions?
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Since the correct answer has to work for all values of x, we can plug in our own value for x.
Plug in x=2. Then f(x) = f(2) and f(1-x) = f(1-2) = f(-1). The question becomes:
For which of the following functions does f(2) = f(-1)?
Answer choice A:
f(2) = 1-2 = -1.
f(-1) = 1-(-1) = 2.
Doesn't work.
Answer choice B:
f(2) = 1 - 2^2 = -3.
f(-1) = 1 - (-1)^2 = 0.
Doesn't work.
Answer choice C:
f(2) = 2^2 - (1-2)^2 = 4 - 1 = 3.
f(-1) = (-1)^2 - [1-(-1)]^2 = 1-4 = -3.
Doesn't work.
Answer choice D:
f(2) = 2^2 * (1-2)^2 = 4 * 1 = 4.
f(-1) = (-1)^2 * [1-(-1)]^2 = 1 * 4 = 4.
Success!
Answer choice E:
f(2) = 2/(1-2) = -2.
f(-1) = (-1)/[(1-(-1)] = -1/2.
Doesn't work.
The correct answer is D.
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- Gurpinder
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hey Mitch,
using your method, a question such as this one would be

lets say a=1 and b=2
so f(3) = f(1) + f(2)
So the question becomes for which of the following functions does f(1) + f(2) equal f(3)?
Is that right?
using your method, a question such as this one would be

lets say a=1 and b=2
so f(3) = f(1) + f(2)
So the question becomes for which of the following functions does f(1) + f(2) equal f(3)?
Is that right?
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Exactly right!
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- Gurpinder
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Thank you!
For the first time in my life, I understand functions! =)
For the first time in my life, I understand functions! =)
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
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