Hi Everyone,
I've solved this problem as follows:
1) area square = s^2
2) area triangle = 1/2*b*h
3) and s^2=1/2*b*h
Main issue (and time consuming part) for me was to work out/simplify the expression for the area of the triangle and some knowledge of exponents:
4) b=t
5) find h with pythagoras: t^2=h^2+{(1/2)*t}^2 --> h^2=(1-1/4)*t^2, thus, h=t*sqrt(3/4) = t*sqrt(3)*(1/2)
6) plug it back in 3) gives: s^2=(1/2)*t*t*sqrt(3)*(1/2)=sqrt(3)*(1/4)*t^2
7) simplify further and then take root: t/s=2/sqrt(sqrt(3), answer is D.
Hope this helps. Cheers, Joe.
