-
henilshaht
- Junior | Next Rank: 30 Posts
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- Joined: Mon Sep 30, 2019 5:04 pm
$$\frac{^{6^{35}\ -\ 6^{25}\ -\ 2}}{6}$$
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Since 6^35 and 6^25 are divisible by 6, the remainder when each is divided by 6 is 0. Therefore, the remainder is the last term "-2". Of course, the remainder can't be negative, and in such a case, we add 6 to -2 to make it positive (and thus the true remainder can be revealed). Therefore, the remainder is -2 + 6 = 4.henilshaht wrote:$$\frac{^{6^{35}\ -\ 6^{25}\ -\ 2}}{6}$$
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$$\frac{^{6^{35}\ -\ 6^{25}\ -\ 2}}{6} = \frac{^{6^{35}\ -\ 6^{25}\ -\ 6 + 4}}{6}= \frac{^6({6^{34}\ -\ 6^{24}\ -\ 1) + 4}}{6}$$henilshaht wrote:$$\frac{^{6^{35}\ -\ 6^{25}\ -\ 2}}{6}$$
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