We know, y=ax^2 +bx+c, if it is asked that what is the x intercept? or how many intercepts x has, how can I approach it?
Given:
(1) a>0
(2) C=-6
Given:
(1) a>0
(2) C=-6
Have 790 or die
When b^2 - 4ac > 0 --> 2 intercept
When b^2 - 4 ac = 0 --> 1 intercept
When b^2 - 4 ac <0> No intercept
(1) a>0
This does not tell us anything because b^2 - 4ac can be either negative or positive
E.g.:
- If b=1, a = 1, C = 4, 1^2 - 4 x 1 x 4 = 1 - 16 = -15
- If b=5, a = 1, C = 4, 5^2 - 4 x 1 x 4 = 25 - 16 = 9
(2) C=-6
This does not tell us anything because b^2 - 4ac can be either negative or positive
(1) + (2)
b^2: will 0 or positive
- 4ac: will positive
--> We will have 2 intercepts
Where did you get that question btw? Because it is very similar to one I had on the actual GMAT...
