BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

GMAT Prep - Factor problem

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Legendary Member
Posts: 979
Joined: Tue Apr 14, 2009 1:38 amFollowed by: 12 members
Location: Hyderabad, India
Thanked: 49 times
GMAT Score:700
by bubbliiiiiiii » Tue Aug 09, 2011 9:34 pm
Hi,

Can someone please help me with how to approach this problem.

I missed noting down OA for this problem.
Attachments
factor.png
Regards,

Pranay
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Legendary Member
Posts: 1448
Joined: Tue May 17, 2011 9:55 amFollowed by: 53 members
Location: India
Thanked: 375 times

by Frankenstein » Tue Aug 09, 2011 9:42 pm
Hi,
450 = 2*3^2*5^2
Now, n^3 = 450*y = (2)(3^2)(5^2)y
As n and y are integers, y should be of the form (2^2)(3)(5)k^3 where k is an integer, so that
n^3 = (2^3)(3^3)(5^3)k^3 i.e. n = 2*3*5*k.
Now, y = (2^2)(3)(5)k^3
So, k^3 = y/(2^2)(3)(5)
So, y/(2^2)(3)(5) is always integer.
I -> k^3 ->definitely integer
II -> (k^3)(2/3) -> not necessarily an integer
III -> (k^3)(2/5) -> not necessarily an integer

Hence, B
Cheers!

Things are not what they appear to be... nor are they otherwise
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1