GMAT Prep Ques (Artist)

This topic has expert replies
Master | Next Rank: 500 Posts
Posts: 446
Joined: Thu Jul 26, 2007 1:07 pm
Thanked: 6 times

GMAT Prep Ques (Artist)

by dferm » Thu Oct 02, 2008 6:54 pm
Of the paintings that a certain artist created last year, the number of paintings that were unframed was 5 times the number of paintings that were framed. If 48 percent of the unframed paintings and 30 percent of the framed paintings were sold, what percent of the paintings that the artist created last year were sold?

A. 33%
B. 36%
C. 39%
D. 42%
E. 45%

Please Help..
Source: — Problem Solving |

User avatar
Master | Next Rank: 500 Posts
Posts: 316
Joined: Mon Sep 22, 2008 12:04 am
Thanked: 36 times
Followed by:1 members

Re: GMAT Prep Ques (Artist)

by Morgoth » Thu Oct 02, 2008 7:25 pm
dferm wrote:Of the paintings that a certain artist created last year, the number of paintings that were unframed was 5 times the number of paintings that were framed. If 48 percent of the unframed paintings and 30 percent of the framed paintings were sold, what percent of the paintings that the artist created last year were sold?

A. 33%
B. 36%
C. 39%
D. 42%
E. 45%

Please Help..
total paintings = U + F

U = 5F

.48U + .3F = X%(U+F)

.48*5F +.3F = X%(6F)

12/5 F +.3F = X(6F)

(24+3)F/10 = X(6F)

27F/10 = X(6F)

27F/(10*6F) = X

9/20 = X

9/20*100 = X%

9*5 = X% = 45%.

OA?

User avatar
Legendary Member
Posts: 871
Joined: Wed Aug 13, 2008 7:48 am
Thanked: 48 times

by stop@800 » Thu Oct 02, 2008 7:42 pm
Solved with example

A very easy method...........


let total 600


framed 100
unframed 500

48% unframed = 48*5 = 240
30% framed = 30

270/600

= 45%

Master | Next Rank: 500 Posts
Posts: 446
Joined: Thu Jul 26, 2007 1:07 pm
Thanked: 6 times

by dferm » Thu Oct 02, 2008 7:42 pm
I would have to get back to u on that but i think that is the correct answer... i don't know how you are arriving @ ur answer...

Senior | Next Rank: 100 Posts
Posts: 31
Joined: Sun Jul 27, 2008 12:41 pm
Location: New York, NY
Thanked: 2 times

by Azntycoon » Thu Oct 02, 2008 7:42 pm
What's the answer? I get E, and here's how I got there:

Let "framed" = F
Let "unframed" = U

i) We can infer from the first sentence that U = 5F
ii) From the second sentence, Total sold = 0.48U + 0.3F
iii) The % of Total Sold to Total Paintings is:
(0.48U + 0.3F)/(U + F)
iv) Substitute "5F" into "U", so you get:
(0.48(5F) + 0.3F)/(5F + F)
v) Solve, and you will get 2.7F/6F
vi) Eliminate the F's and solve 2.7/6 = 0.45

User avatar
Legendary Member
Posts: 871
Joined: Wed Aug 13, 2008 7:48 am
Thanked: 48 times

by stop@800 » Thu Oct 02, 2008 7:43 pm
dferm wrote:I would have to get back to u on that but i think that is the correct answer... i don't know how you are arriving @ ur answer...
Doubt at what point??

Master | Next Rank: 500 Posts
Posts: 446
Joined: Thu Jul 26, 2007 1:07 pm
Thanked: 6 times

by dferm » Thu Oct 02, 2008 7:45 pm
Stop 800 ur correct... thanks for that strategy..........i was trying to solve it algebraically but couldn't figure it out....

Master | Next Rank: 500 Posts
Posts: 446
Joined: Thu Jul 26, 2007 1:07 pm
Thanked: 6 times

by dferm » Thu Oct 02, 2008 7:47 pm
Thanks guys for ur methods....

Legendary Member
Posts: 574
Joined: Sun Jun 01, 2008 8:48 am
Location: Bangalore
Thanked: 28 times

by vishubn » Thu Oct 02, 2008 7:50 pm
My thought as well If this helps u :)

percentage problem ! best approach plug in !!

i randomly chose:

total number of paintings he made =120

Unframed = 5 times the framed

Framed : Unframed = 1:5

which is 20:100

now 48 % of Unframed sold =48 paintings
30% of framed sold=6 paintings

total 54 sold out of 120

(54/120 )*100= 45%

HTH
vishu

Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pm
Thanked: 331 times
Followed by:11 members

by cramya » Fri Oct 03, 2008 4:30 pm
Vishu same here with choosing 120

Any number and 5 times that shouls work for calculating the total to obtain the actual percent painting sold.