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Gmat prep Test 2-- Each of the numbers w,x,y,z

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by ksh » Mon May 26, 2008 11:25 pm
stem1. (8w+4x+2y+z)/16=11/16
so, (8w+4x+2y+z)=11 which can be possible when w,y,z each are 1 and x=0 so, Suff
Similarly,
stem2. (27w+9x+3y+z)=31,which can be possible when w,y,z each are 1 and x=0 so, Suff

hence D
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by khurram » Tue May 27, 2008 6:09 am
Thanks
That is how I did it.
Thanks
khurram
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