raj44 wrote:In how many different orders can the people Alice, Benjamin, Charlene, David, Elaine, Frederick, Gale, and Harold be standing on line if each of Alice, Benjamin, Charlene must be on the line before each of Frederick, Gale, and Harold?
a.1008
b.1296
c.2016
d.1512
e.2268
Number of options for D = 8. (Any of the 8 positions.)
Number of options for E = 7. (Any of the 7 remaining positions.)
A, B and C must stand leftward of F, G and H.
Implication:
Of the 6 positions left, A, B and C must occupy the 3 most leftward.
Number of options for A = 3. (Any of the 3 most leftward positions.)
Number of options for B = 2. (Either of the 2 remaining most leftward positions.)
Number of options for C = 1. (Only 1 of the most leftward positions remains.)
Only 3 positions remain for F, G and H.
Number of options for F = 3. (Any of the 3 remaining positions.)
Number of options for G = 2. (Either of the 2 remaining positions.)
Number of options for H = 1. (Only 1 position remains.)
To combine the options above, we multiply:
8*7*3*2*1*3*2*1 = 2016.
The correct answer is
C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at
[email protected].
Student Review #1
Student Review #2
Student Review #3
I had deliberately interchanged the options - is it always true that options in gmat will be in ascending order?
