Solve this not using calculus? I assume that was what you were asking.pahwa wrote:John plans to fence rectangular garden with 128feet of wire. How can he get maximum area?
Please write the reasoning as well.
Hint: This has something to do with my Tip 1 from Tip of the day thread.
Attempt this question for your practice
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ldoolitt
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samirpandeyit62
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128 feet = perimeter
so sum of sides = 64 feet
area = l*b
so to maximise area we need to maximise the product of l * b which would be highest when l=b = 32
area = 32^2
so sum of sides = 64 feet
area = l*b
so to maximise area we need to maximise the product of l * b which would be highest when l=b = 32
area = 32^2
Regards
Samir
Samir
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jangojess
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ya square will have maximum area.....so max area = (128/4)^2 = 1024...
The same with li'll twist....John has a wire with 128 ft long. wht will be the max area obtained???
The same with li'll twist....John has a wire with 128 ft long. wht will be the max area obtained???
Trying hard!!!
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jangojess
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pahwa....u r partially correct...in ur Q u've mentioned that a rectangular fence needs to be fenced...square will have max area in a quadrilaterals for a fixed perimeter but when it comes to a 2d figure ALWAYS a circle wins......... 
Trying hard!!!
