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by saurabhmahajan » Sat Oct 23, 2010 9:33 am
Please explain
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by diebeatsthegmat » Sat Oct 23, 2010 11:10 am
saurabhmahajan wrote:Please explain
xyz>0 if x>0
1/ x*y>0 => (1) x>0 and y>0 => z>0 (xyz>0)
or (2) x<o ,y<0 => z<0 cos xyz>0 insufficient
2/ xz>0 => or x>0 z>0 => y>0 or x<0 z<0 y>0 insufficient
(1+2) we see that we can take z>0 so y>0 and x>0 sufficient
C
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