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magical cook
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B. 12 --> i.e. x=2, y=3.
Both fractional terms are equal. The first term would constitute 1/3 of k, the second term would constitute 2/3 of k.
B: k=12, therefore (x/(x+y))*10 = 4, (x/(x+y))*20 = 8.
Therefore, x=4, x+y=10, y=6
A: can't work because 10 is not divisible by 3.
C: can't work because both fractional terms have to equal 1/2 (which only works when x=y)
D: can't work because 1/2 of k would be 6, 2/3 of k would be 12.
(x/(x+y))*10=6, (x/(x+y))*20=12
Therefore, x=6, x+y=10, y=4, and x>y (which violates the rule)
E: can't work because both fractional terms have to equal 1 (which is impossible since x<y, so y can't=0; if x=0, the entire fraction equals 0.)
