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by mindruna » Fri Aug 03, 2007 4:03 pm
This is the way I usually do it:

200-100= 100

100/3=33.33

Answer is 33
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by RM » Fri Aug 03, 2007 10:35 pm
3 x 34 = 102 (First Integer b/w 100-200, divisible by 3)
3 x 35 =105
.
.
3 x 66 = 199(Last Integer b/w 100-200, divisible by 3)

Therefore, number of integers between 100-200 divisible by 3 equals
66 - 34 + 1 = 33
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by gabriel » Sat Aug 04, 2007 12:07 am
mindruna wrote:This is the way I usually do it:

200-100= 100

100/3=33.33

Answer is 33
.. U know what .. that need not always be true ...

.. consider the example of the interval 200 - 300 .. applying ur method we would arrive at the conclusion that 33 numbers are divisible by 3 .. but in reality in the interval 200 - 300 there are 34 numbers divisible 3 ..

.. it all depends if the first number of the series is divisible by 3 ..

.. just to be safe i would go with RM's method ...
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by mindruna » Sat Aug 04, 2007 4:32 am
You guys are totally right. Thanks for the correction!
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by radhika1306 » Tue Aug 07, 2007 4:26 am
thanks guys:)
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by recocollins » Tue Aug 07, 2007 10:41 am
The question asks how many integers btw 100-200. Thus the beginning and ending numbers aren't included so thus can't be counted.
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by beny » Tue Aug 07, 2007 5:24 pm
recocollins wrote:The question asks how many integers btw 100-200. Thus the beginning and ending numbers aren't included so thus can't be counted.
The begining and ending numbers aren't divisible by 3 anyway...
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Another Shortcut

by gmatz » Wed Aug 08, 2007 7:12 am
Here is the way I look at these. If you're looking for multiples of 3 between 100 - 200, you can rephrase the question as how many integers are between 102 - 198 inclusive? So 198 - 102 = 96. 96/3 = 32 + 1 = 33. Remember you add 1 (which is representing a set of consecutive numbers) because the rephrased statement says [u]inclusive[/u].
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Another Shortcut

by gmatz » Wed Aug 08, 2007 7:13 am
Here is the way I look at these. If you're looking for multiples of 3 between 100 - 200, you can rephrase the question as how many integers are between 102 - 198 inclusive? So 198 - 102 = 96. 96/3 = 32 + 1 = 33. Remember you add 1 (which is representing a set of consecutive numbers) because the rephrased statement says [u]inclusive[/u].
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