1 - Sufficient.sneakpeek wrote:Each of the numbers w,x,y, and z is equal to either 0 or 1. What is the value of w+x+y+z?
(1) w/2 + x/4 + y/8 + z/16 = 11/16
(2) w/3 + x/9 + y/27 + z/81 = 31/81
Take the LCM and sum up the numerator
(8w + 4x + 2y + z) / 16
Since w, x, y and z are either 0 or 1, only possible combination
is w=1, x=0, y=1, z=1
2 - Sufficient.
(27w + 9x + 3y + z) / 81
Only w=1, x=0, y=1 and z=1 satisfy the above condition
Is it D ?












