BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATBootcamp Starts Sep 28
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE BOOTCAMP

Live Online Bootcamp Class with Top GMAT Expert Chris Peckover

15 live classes from Sep 28, 2026

Schedule
Mon to Fri · 7:00 to 10:00 PM ET
Included
Live classes + 6 months of TTP OnDemand
  • Boost your GMAT score in less than one month in a live online class
  • 6 months access to TTP OnDemand video courses included
View bootcamp & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

DS question

Expert replies
by gviren » Sat May 19, 2007 11:35 am
Hi,

I thought the answer is B) but correct answer is E). Please explain

Are the numbers k/4,z/3 and r/2 in increasing order?
(1) 3 < z < 4
(2) r < z < k

My logic is.....

k/4<z/3<r/2

or after multiplying by 12 ---> 3k < 4z < 6r and we have r<z<k

pick numbers
r=1, z=2, k=3 so we have 9 < 8 < 6 not true

pick numbers
r=1, z=8, k=12 so we have 36 < 32 < 6 not true

pick numbers
r=-1, z=0, k=12 so we have 36 < 0 < -6 not true

So we know that this is never true

Please let me know whats wrong with my logic here
Join the discussion
Source: — Data Sufficiency |

Re: DS question

by jayhawk2001 » Sat May 19, 2007 1:04 pm
gviren wrote:Hi,

I thought the answer is B) but correct answer is E). Please explain

Are the numbers k/4,z/3 and r/2 in increasing order?
(1) 3 < z < 4
(2) r < z < k
For (2), one simple test is k=4, z=3 and r=2

r<z<k but k/4, z/3 and r/2 are all equal.

Just vary r from 2 to 2.2 and you'll see the condition is no longer true.
Hence insufficient.
Join the discussion

by maolivie » Mon May 21, 2007 7:08 am
or just put r as a negative number. the condition doesn't maintain its clause
Join the discussion

by Cybermusings » Mon May 21, 2007 8:41 am
Consider the situation when r < z < k where r = 2, z=3 and k = 4; here r/2 = z/3 = k/4 = 1

Hence insufficient since you'll get varying answers
Join the discussion