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GMAT prep - a couple more

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Source: — Data Sufficiency |
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by Cybermusings » Mon May 21, 2007 9:47 am
Free selection of 3 apples without conditions = 10C3 = 120
Selection of 2 red apples and 1 green apple = 7C2 * 3C1 = 21*3 = 63
Hence probability = 63/120 = 21/40
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