If the operation D is one of the four arithmetic operations addition, subtraction, multiplication and division, is (6 D 2) D 4 = 6 D (2 D 4)
1. 3 D 2 >3
2. 3 D 1 = 3
Ans = A
I am getting C and here is how I have solved it
From 1 D can be either + or X (because 3 +2 >3 and 3 X 2>3) - not sufficient
From 2 D can be either division or X - Insufficient
Combining the 2, multiplication satisfies both 1 and 2, so C
1. 3 D 2 >3
2. 3 D 1 = 3
Ans = A
I am getting C and here is how I have solved it
From 1 D can be either + or X (because 3 +2 >3 and 3 X 2>3) - not sufficient
From 2 D can be either division or X - Insufficient
Combining the 2, multiplication satisfies both 1 and 2, so C
