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Source: — Data Sufficiency |
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by 800GMAT » Sat May 19, 2007 2:57 pm
any approach to solve this.......??
Thnks
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by jayhawk2001 » Sat May 19, 2007 4:52 pm
Darn, this was a toughie...

Is it D ?

Lets assume Fx and Fy = full-time employees in x and y resp
Similarly, Px and Py = part-time employees in x and y resp

We are asked to find if

Fx/Px > (Fx+Fy) / (Px+Py)
i.e.
Fx/Px > Fx/Px [ (1+Fy/Fx) / (1+Py/Px) ]
1 > (1+Fy/Fx) / (1+Py/Px)
1 + Py/Px > 1 + Fy/Fx
Py / Px > Fy/Fx
or
Fx/Px > Fy/Py


1 - sufficient.

Fy/Py > (Fx+Fy) / (Px+Py)
Fy/Py > Fy/Py [ (1+Fx/Fy) / (1+Px/Py) ]
Fy/Py > Fx/Px
So, sufficient.

2 - sufficient.

(Fx+Fy) / (Px+Py)
= Fx/Px [ (1+Fy/Fx) / (1 + Py/Px) ]

We are given Fy/Fx < 1 and Py/Px > 1
So, ratio for Z less than Fx/Px. So, sufficient.
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by 800GMAT » Sat May 19, 2007 5:00 pm
Thanks jayhawk.......

Since It is a ratio that we are asked to compare, I picked numbers to solve this...


You are right..the answer is D
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by jayhawk2001 » Sat May 19, 2007 5:08 pm
800GMAT wrote:Thanks jayhawk.......

Since It is a ratio that we are asked to compare, I picked numbers to solve this...

You are right..the answer is D
On the real test, I'd vote for choosing numbers too :-).

I was just trying to explain this mathematically using an equation
:idea:
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