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Bowls X and Y

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by jsl » Thu Nov 06, 2008 5:31 am
Bowls X and Y each contained exactly 2 jelly beans, each of which was either red or black. One of the jelly beans in bowl X was exchanged with one of the jelly beans in bowl Y. After the exchange, were both of the jelly beans in bowl X black?

1) Before the exchange, bowl X contained 2 black jelly beans
2) After the exchange, bowl Y contained 1 jelly bean of each color
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Source: — Data Sufficiency |
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by cramya » Thu Nov 06, 2008 6:19 am
I would go with E)

Please post OA
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Re: Bowls X and Y

by jimmiejaz » Thu Nov 06, 2008 7:46 am
how about this twist cramya????

Bowls X and Y each contained exactly 2 jelly beans, each of which was either red or black. One of the jelly beans in bowl X was exchanged with one of the jelly beans in bowl Y. After the exchange, what is the probability that both of the jelly beans in bowl X are black?

Confused here....
Pls throw some light
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by 4meonly » Thu Nov 06, 2008 8:46 am
Agree with E

Possibility 1.
Before exchange
X: BB, Y: RR.
After exchange
X: RB, Y: BR.
Different

Possibility 2.
Before exchange
X: BB, Y: RB.
After exchange
X: BB, Y: RB.
Both black
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by jsl » Thu Nov 06, 2008 8:49 am
OA E
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by Fab » Thu Nov 06, 2008 2:24 pm
Why not C ?

2) After the exchange, bowl Y contained 1 jelly bean of each color.

That means that before the exchange both jellys at Y were red.

Correct me if I'm wrong.

THANKS
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by 4meonly » Sun Nov 09, 2008 10:52 am
look through my post
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by jayjk78 » Mon Nov 10, 2008 9:12 pm
I think B

Stm 1 X had both black...but Y may have both black as well so not suff

Stm2 After the exchange Y has one of each color. Possible only if the bowls have different color bowls. After exchange if Y has Red and Black then before it had either both red or both black. Hence X as well had either both red or both black. This statement answers the q/s that X does not have both black after exchange
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