a five member committee is to be formed from a group of five x and 9 y. if the committee must have at least 2 x and 2 y, in how many diff ways can the committee be chosen.
ans is 1200.
I get 3600.
5!/2!3! * 9/2!7! *10=3600
solution says 1200 as not 2 but 3 ! for one group so 1200 as we will have 3 possible arrangements from the groups we choose.
Thanks very much
ans is 1200.
I get 3600.
5!/2!3! * 9/2!7! *10=3600
solution says 1200 as not 2 but 3 ! for one group so 1200 as we will have 3 possible arrangements from the groups we choose.
Thanks very much
