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PS 14

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by magical cook » Wed Nov 28, 2007 10:51 am
C(m,n) = m! / [(m-n)! n!] for nonnegative integers m and n, m ³ n. If C(5,3) = C(5,x) and x ¹
3, what is the value of x?
A. 0
B. 1
C. 2
D. 4
E. 5

Hi, somehow I got it wrong. hope someone could help...
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Re: PS 14

by gabriel » Thu Nov 29, 2007 2:41 am
magical cook wrote:C(m,n) = m! / [(m-n)! n!] for nonnegative integers m and n, m ³ n. If C(5,3) = C(5,x) and x ¹
3, what is the value of x?
A. 0
B. 1
C. 2
D. 4
E. 5

Hi, somehow I got it wrong. hope someone could help...
According to the given information C(5,3)= 5!/(3!*2!) ... and C(5,x) = 5!/((5-x)!*x!) .. now if you compare the 2 denominators you will see that only x = 2 will give the values 3 and 2 (which is what we want if they have to be equal) in the denominator, so the answer is C, that is x = 2..

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by magical cook » Thu Nov 29, 2007 7:43 am
Hi gabriel - got it - thanks!
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