BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Gmat Prep divisibilty remainders

Expert replies
by sdotcruz » Sat Nov 27, 2010 6:00 am
this problem is from the Gmat Prep software. I understand what is being asked, but do not know how to determine the value.


If n is a positive integer and r is the remainder when 4+7n is divided by 3, what is the value of r?

1. n+1 is divisible by 3

2. n>20


OA: A
Join the discussion
Source: — Data Sufficiency |

by shovan85 » Sat Nov 27, 2010 6:28 am
sdotcruz wrote: If n is a positive integer and r is the remainder when 4+7n is divided by 3, what is the value of r?

1. n+1 is divisible by 3

2. n>20
Option 1:

n+1 is divisible by 3

So, n+1 = 3k (k is any integer)

=> n = 3k - 1

Now, 4 + 7n

= 4 + 7(3k - 1)

= 4 + 21k - 7

= 21k - 3

for any value of k, 21k - 3 is divisible by 3. Thus r = 0. Sufficient.

Option 2: n > 20

Then 4 + 7n can be any value with n greater than 20.

When n = 21, 4 + 7n = 151. Thus remainder = 1

When n = 22, 4 + 7n = 158. Thus remainder = 2

So we do not have a concrete value of r. Thus, Not sufficient.

IMO A
If the problem is Easy Respect it, if the problem is tough Attack it
Join the discussion

by Rahul@gurome » Sat Nov 27, 2010 6:31 am
sdotcruz wrote:If n is a positive integer and r is the remainder when 4+7n is divided by 3, what is the value of r?
1. n+1 is divisible by 3
2. n>20

OA: A
Given: When (7n + 4) is divided by 3, the remainder is r.

Statement 1: (n + 1) is divisible by 3.
Implies 7(n + 1) is divisible by 3.
=> (7n + 7) is divisible by 3.
=> (7n + 4 + 3) is divisible by 3.
=> (7n + 4) is divisible by 3.

This is because if a number x is divisible by 3, then (x - 3) will also be divisible by 3.

Thus r = 0.

Sufficient.


Statement 2: n > 20
Value of r may be 0, 1 or 2 according to the value of n.

Not sufficient.

The correct answer is B.
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Join the discussion

by rishab1988 » Sat Nov 27, 2010 7:32 am
Here is how I approached this problem and most GMAT problems.Simplify the prompt as much as you can.

We know n is an integer and (4+7n)/3 will give a remainder r.

Lets assume n=1 11/3. Rem =2
n=2 18/3 rem=0
n=3 25/3 rem =1
n=4 32/3 rem =2
n=5 39/3 rem =0


You can see a pattern : 2,0,1,2,0,1,2... So if we know n we can find what the remainder is.

When the term is 2nd,5th,8th,11th the rem =0
When the term is 1st,4th,7th,10th the rem =2
When the term is 3rd,6th,9th the rem =1

1) n+1 divisible by 3. if n =2 .n+1 is divisible by 3. Rem @ n=2 is 0.

When n+1=6 or n =5 rem 0

n+1=9 n-> 8 rem = 0

In general you can say n->2,5,8,11,14.See it matches with value 0

Sufficient.

2) This is clearly insufficient as n could be 21,or 22,or 23 or anything.

For 21. rem =1
For 22 rem =2.

Multiple values.hence insufficient.

Answer should be A
Join the discussion

by rishab1988 » Sat Nov 27, 2010 7:40 am
Alternatively,you can also use this logic ; when you either add or subtract a multiple of a number X to another multiple of same number X.

Eg: 22 is a multiple of 11 right?

we also know 110 is a multiple of 11.

Add 22 to 110 .You get 132-another multiple of 11.

Subtract 22 from 110,you get 88-another multiple of 11.

Prompt "IS (4+7n)/n = integer"?

1) n+1 is a multiple of 2.

Now if subtract a multiple a multiple of 3 from another multiple of 3,the result too would be a multiple of 3 right?

Applying this (4+7n)-(n+1) = 6n+3 = 3(2n+1).

Since it has a factor of 3.We can say that it is divisible by 3.Therefore 4+7n too is.

2) n>20

use n=30 -> 4+210 = 214. Sum of digits -> 7 .remainder must be 1.
use n=40 -> 4+280 = 284 Sum of digits -> 14 .remainder must be 2.

Insufficient.

Hence A
Join the discussion

by tomada » Sun Nov 28, 2010 5:17 pm
FYI, you accidentally typed that the correct answer is B.

Rahul@gurome wrote:
sdotcruz wrote:If n is a positive integer and r is the remainder when 4+7n is divided by 3, what is the value of r?
1. n+1 is divisible by 3
2. n>20

OA: A
Given: When (7n + 4) is divided by 3, the remainder is r.

Statement 1: (n + 1) is divisible by 3.
Implies 7(n + 1) is divisible by 3.
=> (7n + 7) is divisible by 3.
=> (7n + 4 + 3) is divisible by 3.
=> (7n + 4) is divisible by 3.

This is because if a number x is divisible by 3, then (x - 3) will also be divisible by 3.

Thus r = 0.

Sufficient.


Statement 2: n > 20
Value of r may be 0, 1 or 2 according to the value of n.

Not sufficient.

The correct answer is B.
I'm really old, but I'll never be too old to become more educated.
Join the discussion