Value of X - Exponents

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Re: Value of X - Exponents

by netigen » Sat Mar 08, 2008 3:16 pm
adi wrote:If (2^x) - (2^x-2) = 3(2^13), what is the value of x?

A) 9
B) 11
C) 13
D) 15
E) 17

The answer should be D.
Equate the equation
(2^x) - (2^[x-2]) = (2^x) [1 - (2^[-2])] = (2^x) [1 - 1/4] = 3/4 x 2^x

3/4 x 2^x = 3(2^13)

2^(x-2) = (2^13)

x-2 = 13

x= 15

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by adi » Sat Mar 08, 2008 3:50 pm
How did you make (2^x) - (2^[x-2]) = (2^x) [1 - (2^[-2])]

Also, where did the - go in (2^x) - (2^[x-2])

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by tony777 » Sun Mar 09, 2008 4:47 am
(2^x) - (2^[x-2]) = (2^x) [1 - (2^[-2])]

In netigen's response he/she factored (2^x) - (2^[x-2]) to bring 2^x out.

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Shortest Way to Solve

by opengmat » Fri Mar 14, 2008 11:45 pm
The shortest to solve is by plug-in answer choice and equate both sides.

here start with C > LHS < RHS [x=13]
Goto next choice D > LHS = RHS [x=15]

Pls comment,

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backsolving

by resilient » Tue Mar 18, 2008 12:03 am
this is a fairly involved question. I would definintely try to backsolve on this question. It is begging to be back solved. In fact, I dont even see how to equate the equation.
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by xilef » Tue Mar 18, 2008 12:44 pm
once you realize that (2^x-2) is 2^x/2^2 then:

2^x-(2^x/2^2)=3(2^13)
2^x(1-1/4)=3(2^13)
2^x(3/4)=3(2^13)
2^x=4(2^13)
2^x=2^2(2^13)
2^x=(2^15)

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by hillzheng » Wed Apr 16, 2008 10:29 pm
yes, x=15 or answer be D

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by aj5105 » Thu May 07, 2009 10:39 pm

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by pacogzza » Mon Aug 23, 2010 5:33 pm
Sorry guys, I did not get the process of how you guys went through this problem... Could you go over this prob again and explain it for dummies plz??

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