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Expert replies
by rommysingh » Thu Sep 03, 2015 10:31 am
It takes the high-speed train x hours to travel the z miles from Town A to Town B at a constant rate, while it takes the regular train y hours to travel the same distance at a constant rate. If the high-speed train leaves Town A for Town B at the same time that the regular train leaves Town B for Town A, how many more miles will the high-speed train have traveled than the regular train when the two trains pass each other?
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by DavidG@VeritasPrep » Thu Sep 03, 2015 10:51 am
It takes the high-speed train x hours to travel the z miles from Town A to Town B at a constant rate, while it takes the regular train y hours to travel the same distance at a constant rate. If the high-speed train leaves Town A for Town B at the same time that the regular train leaves Town B for Town A, how many more miles will the high-speed train have traveled than the regular train when the two trains pass each other?
Pick some simple numbers. Let's say x = 2 and z = 100, so the high-speed train takes 2 hours to go 100 miles. So the high-speed train goes 100/2 = 50mph.

Let's say y = 4 and the regular train takes 4 hours to go 100 miles, so the regular train goes 100/4 = 25mph.

Let's say that they're traveling for t hours. We know that the high-speed train will cover 50t miles. (Rate* Time)
We know that the regular train will cover 25t miles.

They're starting 100 miles apart, so combined, they travel 100 miles. This gives us the following equation: 25t + 50t = 100 --> 75t = 100 --> t = 100/75 = 4/3

So the high-speed train will have gone a total of 50 * (4/3) = 200/3 miles
And the regular speed train will have gone a total of 25 *(4/3) = 100/3 miles
And the high-speed train will have gone 200/3 - 100/3 = 100/3 more miles than the regular speed train.

Now we substitute x = 2, z = 100, and y = 4 into the answer choices and see which gives us 100/3.

A gives us [100(4-2)]/(4+2) = 200/6 = 100/3. Done! That's our answer.
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by DavidG@VeritasPrep » Thu Sep 03, 2015 10:57 am
(You could also reason this out a little more quickly. If x = 2 and y = 4, then the high-speed train is taking half as much time to complete the trip then the regular speed train, which means that the high-speed train's rate is double the regular train's rate. If z = 100, and they go 100 miles total to meet, the high-speed train will have covered twice the distance that the regular train covered. Therefore, the high speed train covers 66 2/3 miles, and the regular train covers 33 1/3 miles. High speed train then covers 33 1/3 more miles than the regular train. Plugging x = 2, y=4, and z = 100 into A will give you 100/3 or 33 1/3.)
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