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GMAT Prep question

Expert replies
Source: — Problem Solving |

by Brent@GMATPrepNow » Sun Sep 28, 2014 12:21 pm
anksm22 wrote:if 0<r<1<s<2 which of the following must be less than 1?

a. r/s
b. rs
c. s-r

A a only
B b only
C c only
D a and b only
E a and c only
a. r/s
r and s are both POSITIVE, and r is less than s.
So, it MUST be the case that r/s < 1


b. rs
It could be the case that r = 0.9 and s = 1.8, in which case rs = 1.62
So, it NEED NOT be the case that rs < 1

c. s - r
It could be the case that r = 0.1 and s = 1.8, in which case s - r = 1.7
So, it NEED NOT be the case that s - r < 1

Answer: A

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by ianurag » Sun Sep 28, 2014 8:45 pm
Its A
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by j_shreyans » Sun Sep 28, 2014 11:11 pm
Hi Brent ,

In B) rs

IF i test the value like:

r=0.5 and s=1.5 then rs will less than 1(0.75)

and
r=0.7 and s=1.9 then rs will be greater than 1(1.33)

so we will remove this option right? because it's not giving unique information.

Pls correct me if i am wrong.
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by [email protected] » Mon Sep 29, 2014 12:03 am
Hi j_shreyans,

When the question asks "which of the following MUST be less than 1" what it's really asking is "which of the following is ALWAYS less than 1 no matter how many different options you try?"

In these situations, the most efficient way to deal with the prompt is to prove the OPPOSITE of what it asks for. In your second example, you proved that RS is NOT always less than 1, so Roman Numeral II is not going to be listed in the correct answer (and your first example isn't even necessary).

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by GMATGuruNY » Mon Sep 29, 2014 2:58 am
anksm22 wrote:if 0<r<1<s<2 which of the following must be less than 1?

a. r/s
b. rs
c. s-r

A a only
B b only
C c only
D a and b only
E a and c only
0 < r < 1.
1 < s < 2.

An alternate approach is to perform the 3 operations -- r/s, rs, and s-r -- using EVERY COMBINATION OF ENDPOINTS.
Here, there are four endpoints to consider:
lower limit for r = 0.
upper limit for r = 1.
lower limit for s = 1.
upper limit for s = 2.

a: r/s
(lower limit for r)/(lower limit for s) = 0/1 = 0.
(lower limit for r)/(upper limit for s) = 0/2 = 0.
(upper limit for r)/(lower limit for s) = 1/1 = 1
(upper limit for r)/(upper limit for s) = 1/2 = 1/2.

The smallest result -- 0 -- is the lower limit for r/s.
The greatest result -- 1 -- is the upper limit for r/s.
Thus:
0 < r/s < 1.

Since r/s must be less than 1, the correct answer choice must include a.
Eliminate B and C.

b: rs
(lower limit for r)/(lower limit for s) = 0*1 = 0.
(lower limit for r)/(upper limit for s) = 0*2 = 0.
(upper limit for r)/(lower limit for s) = 1*1 = 1
(upper limit for r)/(upper limit for s) = 1*2 = 2.

The smallest result -- 0 -- is the lower limit for rs.
The greatest result -- 2 -- is the upper limit for rs.
Thus:
0 < rs < 2.

Since rs does NOT have to be less than 1, the correct answer choice cannot include b.
Eliminate D.

c: s-r
(lower limit for s)/(lower limit for r) = 1-0 = 1.
(lower limit for s)/(upper limit for r) = 1-1 = 0.
(upper limit for s)/(lower limit for r) = 2-0 = 2.
(upper limit for s)/(upper limit for r) = 2-1 = 1.

The smallest result -- 0 -- is the lower limit for s-r.
The greatest result -- 2 -- is the upper limit for s-r.
Thus:
0 < s-r < 2.
Since s-r does NOT have to be less than 1, the correct answer choice cannot include c.
Eliminate E.

The correct answer is A.
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