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gmat prep question

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Source: — Data Sufficiency |

Re: gmat prep question

by Prasanna » Mon May 28, 2007 4:09 pm
yvonne12 wrote:if c and d are integers, is c even

1. c(d+1) is even
2. (c+2) (c+4) is even
Is the answer B.

(1) c(d+1) is even. This could be the case when c and d is even or when c and d is odd. Hence not sufficient

(2) (c+2)(c+4) is even. This means c should be even. Hence sufficient.
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by jayhawk2001 » Mon May 28, 2007 6:25 pm
Another B
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no

by yvonne12 » Mon May 28, 2007 7:03 pm
no the answer is c
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by mendiratta » Wed May 30, 2007 3:53 am
Agree with C. (Though my first guess was also B :evil: )

1. Clearly INSUFF as explained by Prasanna.
2. This stmt guarantees that C is even in all the cases except when C = 0; this statement is true but it doesn't tells about C (because 0 is neither even nor odd)- so INSUFF.

But if we combine both, first statement tells that C is not zero. (because something multiplied by C is even).

Therefore C.
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by jayhawk2001 » Wed May 30, 2007 6:58 am
mendiratta wrote:Agree with C. (Though my first guess was also B :evil: )

1. Clearly INSUFF as explained by Prasanna.
2. This stmt guarantees that C is even in all the cases except when C = 0; this statement is true but it doesn't tells about C (because 0 is neither even nor odd)- so INSUFF.

But if we combine both, first statement tells that C is not zero. (because something multiplied by C is even).

Therefore C.
Hmm, OG quants (Green book) tells us that the sequence -4, -2, 0, 2, 4 ...
is even.

I just checked wikipedia and it says 0 is even as well.

https://en.wikipedia.org/wiki/Even_and_odd_numbers

Not sure how it can be C, given the above...
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by dunkin77 » Sat Jun 09, 2007 1:12 pm
mendiratta,

To make (c+2)(c+4) zero, C must be either -2 or -4 which is also even... so I think it's B. confusing...

anyone confirm OA again??
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