BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

If m and v are integers, what is the value of m + v?

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Data Sufficiency |
Junior | Next Rank: 30 Posts
Posts: 19
Joined: Sat Feb 07, 2009 9:00 am
Thanked: 1 times

by AJ2009 » Fri Feb 20, 2009 12:43 pm
I go for E.
Am I missing a trap?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 68
Joined: Sun Dec 21, 2008 12:00 am
Thanked: 3 times

by ontopofit » Fri Feb 20, 2009 12:44 pm
E it is
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 44
Joined: Tue Feb 03, 2009 5:17 am

by mridula » Fri Feb 20, 2009 12:49 pm
E is the correct answer, but i thought it should be C.

from statement 2,
(m+v)^2 = 25. so, (m+v) = + or -5.

from statement 1, mv=6. Since m and v are integers, they can be, 2 and 3 or 6 and 1, but only the values 2 and 3 satisfy the first statement.
So, m+v = 5.

So, both statements together are sufficient.

What did i mess up here?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 279
Joined: Wed Sep 24, 2008 8:26 am
Location: Portland, OR
Thanked: 6 times

by pbanavara » Fri Feb 20, 2009 4:01 pm
mridula wrote:E is the correct answer, but i thought it should be C.

from statement 2,
(m+v)^2 = 25. so, (m+v) = + or -5.

from statement 1, mv=6. Since m and v are integers, they can be, 2 and 3 or 6 and 1, but only the values 2 and 3 satisfy the first statement.
So, m+v = 5.

So, both statements together are sufficient.

What did i mess up here?
m+v = |5| mv = 6

So m and v can also take values of -3 and -2 or -6 and -1. Hence this is not sufficient.
In the land of night, the chariot of the sun is drawn by the grateful dead
https://questor.blocked

GMATPREP1 - 550 (Oct 08)
MGMAT FREE CAT - 600 (Dec 08)
MGMAT CAT1 - 670 (Jan 09)
MGMAT CAT2 - 550 (Jan 09)
MGMAT CAT3 - 640 ( Feb 09)
MGMAT CAT4 - 660 ( Feb 09)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 80
Joined: Thu Jan 31, 2008 9:15 pm
Thanked: 2 times

by linfongyu » Fri Mar 20, 2009 12:26 pm
mridula wrote:E is the correct answer, but i thought it should be C.

from statement 2,
(m+v)^2 = 25. so, (m+v) = + or -5.

from statement 1, mv=6. Since m and v are integers, they can be, 2 and 3 or 6 and 1, but only the values 2 and 3 satisfy the first statement.
So, m+v = 5.

So, both statements together are sufficient.

What did i mess up here?
I did the same thing, then I realized...

1) mv=6, (1,6),(-1,-6),(2,3),(-2,-3)

2) (m+v)^2=25, m+v= 5, -5

Combine, (m,v) = (2,3) or (-2,-3). m*v for both are 6, and m+v= 5 or -5. Not sufficient.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 147
Joined: Tue Jun 14, 2011 7:03 am
Thanked: 3 times

by tracyyahoo » Thu Sep 08, 2011 10:45 pm
2*3=6 but -2*-3=6

(2+3)^2=25 but (-2-3)^2=25

so it not just simply m and v are positive, thwy could be nagetive.

COmbine: m+v=5 or m+v=-5, insuff. so it is E

mridula wrote:E is the correct answer, but i thought it should be C.

from statement 2,
(m+v)^2 = 25. so, (m+v) = + or -5.

from statement 1, mv=6. Since m and v are integers, they can be, 2 and 3 or 6 and 1, but only the values 2 and 3 satisfy the first statement.
So, m+v = 5.

So, both statements together are sufficient.

What did i mess up here?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1