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5 consecutive even numbers

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Source: — Problem Solving |

by mals24 » Sun Nov 16, 2008 5:05 am
IMO A

I X is an even integer.
-4-2+0+2+4 = 0
-2+0+2+4+6=10
32+34+36+38=140

The sum of 5 consecutive even integers is always an even integer (and a multiple of 10).
Hence x is always an even integer.

II X is a non zero integer.
-4-2+0+2+4 = 0

0/5= 0
Hence this statement is false.

III X is a multiple of 5
-2+0+2+4+6 = 10
X=10/5=2
2 is not a multiple of 5
Hence this statement is false

Answer is A
Last edited by mals24 on Sun Nov 16, 2008 5:52 am, edited 1 time in total.
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by iamcste » Sun Nov 16, 2008 5:37 am
mals24 wrote:IMO A

I X is an even integer.
-4-2+0+2+4 = 0
-2+0+2+4+6=10
32+34+36+38=140

The sum of 5 consecutive integers is always an even integer (and a multiple of 10).
Hence x is always an even integer.

II X is a non zero integer.
-4-2+0+2+4 = 0

0/5= 0
Hence this statement is false.

III X is a multiple of 5
-2+0+2+4+6 = 10
X=10/5=2
2 is not a multiple of 5
Hence this statement is false

Answer is A

Bingo!
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by stop@800 » Sun Nov 16, 2008 6:00 am
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