To know the slope we need to know the two coordinate points of each line.
With the help of both setms we can get this.
Amit
GPREP1-Slope
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.........but I'm assuming you used a drawing to answer the question instead of getting the actual slope. So, if the Y-int of one line is greater than than of the other line, the line with the greater y-int is steeper and has a higher slope?
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amitansu
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True, a line with higher slope gets steeper...
but i didn't use any drawing or graph.
When two stems need to be combined, then we just need to see whether
the ans is achievable.
Amit
but i didn't use any drawing or graph.
When two stems need to be combined, then we just need to see whether
the ans is achievable.
Amit
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kiran.raze
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Hi Medea,
Well, I guess you are right - a line with higher y intercept would have an obtuse angle with the X axis (as it lies in the first quadrant)i.e a negative slope(change in Y/change in X=tan(angle made by the line with the x axis)as tan(obtuse angle(90<x<180) ='-'. And any line intersecting this line at (5,1) will either have an angle greater than than the angle made by N when obtuse(i.e >90) or any angle between 0 & 90 , and in both these cases the Tan of the angle would be > than the one made by N
therefore we can say that the slope of N would be less than the line P when the intersection point is (5,1) & N is the line which makes a higher Y intercept.
thanks,
Kiran
Well, I guess you are right - a line with higher y intercept would have an obtuse angle with the X axis (as it lies in the first quadrant)i.e a negative slope(change in Y/change in X=tan(angle made by the line with the x axis)as tan(obtuse angle(90<x<180) ='-'. And any line intersecting this line at (5,1) will either have an angle greater than than the angle made by N when obtuse(i.e >90) or any angle between 0 & 90 , and in both these cases the Tan of the angle would be > than the one made by N
therefore we can say that the slope of N would be less than the line P when the intersection point is (5,1) & N is the line which makes a higher Y intercept.
thanks,
Kiran
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sumithshah
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I have a slightly algbric approach.
For each line we can say :
Line N:
y-y1 = M (x-x1) --> equation of a st line
using 5,1
y-1 = M ( x - 5)
or y = Mx - (5M+1)
Line P:
y-y1 = m (x-x1) --> equation of a st line
using 5,1
y-1 = m ( x - 5)
or y = mx - (5m+1)
Using statement 2 we know
Y intercept of N is greater than that of P
hence from the weird stuff done in statement one we can say
-(5M+1) > - (5m+1)
hence you can get the ratio of M/m or m/M ---> Solvable.
For each line we can say :
Line N:
y-y1 = M (x-x1) --> equation of a st line
using 5,1
y-1 = M ( x - 5)
or y = Mx - (5M+1)
Line P:
y-y1 = m (x-x1) --> equation of a st line
using 5,1
y-1 = m ( x - 5)
or y = mx - (5m+1)
Using statement 2 we know
Y intercept of N is greater than that of P
hence from the weird stuff done in statement one we can say
-(5M+1) > - (5m+1)
hence you can get the ratio of M/m or m/M ---> Solvable.