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Triangle

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Source: — Data Sufficiency |
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by Mani_mba » Sat Jul 26, 2008 3:01 am
IMO E.

I would choose A, if i am able to prove BAD and ABD are each x such that their sum equals 2x(exterior angle).

If anybody could prove the above, please post.
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by umaa » Sat Jul 26, 2008 4:04 am
pls check the naswer
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by cubicle_bound_misfit » Sat Jul 26, 2008 6:03 am
i think angle BAD is X.
it is a BAD case of printing mistake.
let me know if that makes sense

regards,
Cubicle Bound Misfit
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by umaa » Sun Jul 27, 2008 7:44 pm
I don't understand. please explain me
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Not sure

by enniguy » Mon Jul 28, 2008 12:42 am
IMO C.

Reasoning:
1. consider any triangle BDC. BDC is an isosceles triangle from question.
Fixing AD = 6, we can vary the height of the triangle BDC varying x. So we cant determine BC.

[Think of it like you can just pull point B up and down with sides as strings]

INSUFFICIENT.

2. Now, if you keep the angle 2x the same, i.e 72 degrees, then you can vary AD to any length and change the size of the triangle (Similar triangles keeping the ratio x:2x:2x).

INSUFFICIENT.

Together, if you fix the angle x and AD, then you cant vary the height of the triangle hence you will be able to find BC.

Please correct me if i am wrong
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