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If x*y does not equal 0 and (x^2) (y^2) - xy = 6, which of t

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by dmateer25 » Sun Dec 14, 2008 5:24 am
(x^2) (y^2) - xy = 6

(x^2) (y^2) - xy - 6 = 0

(xy - 3)(xy+2) = 0
xy = 3 | xy =-2
x=3/x....|..x = -2/x


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