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by Mani_mba » Fri Oct 03, 2008 8:12 pm
3 boys and 3 Girls ===> 2 from each has to be selected totalling to 4 children

Total Number of ways to select 4 children from 6 children = 6C4 = 15 ------------- A

Total Number of ways to select 2 children from 3 boys
And 2 from 3 girls = 3C2 * 3C2 = 9 --------------------- B

The probability is B/A = 9/15 = 3/5
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